[3x-4(x+1)]=2

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Solution for [3x-4(x+1)]=2 equation:


Simplifying
[3x + -4(x + 1)] = 2

Reorder the terms:
[3x + -4(1 + x)] = 2
[3x + (1 * -4 + x * -4)] = 2
[3x + (-4 + -4x)] = 2

Reorder the terms:
[-4 + 3x + -4x] = 2

Combine like terms: 3x + -4x = -1x
[-4 + -1x] = 2

Remove brackets around [-4 + -1x]
-4 + -1x = 2

Solving
-4 + -1x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1x = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -1x = 2 + 4
-1x = 2 + 4

Combine like terms: 2 + 4 = 6
-1x = 6

Divide each side by '-1'.
x = -6

Simplifying
x = -6

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